1991 Indian Challenge
| Tournament information | |
|---|---|
| Dates | 4–7 September 1991 |
| Venue | Taj Palace Intercontinental Hotel |
| City | Delhi |
| Country | India |
| Format | Non-ranking event |
| Total prize fund | £72,000[1] |
| Winner's share | £20,000[2] |
| Highest break | |
| Final | |
| Champion | |
| Runner-up | |
| Score | 9–5 |
The 1991 Indian Challenge was an invitational non-ranking snooker tournament, which took place from 4 to 7 September 1991 at the Taj Palace Intercontinental Hotel in Delhi, India.[1] Stephen Hendry won the title, defeating John Parrott 9–5 in the final, and received £20,000 prize money. Parrott compiled the highest break of the tournament, 132, in the semi-final, having made a 127 break in the preceding frame.[2][3]
Results
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References
- ^ a b "Yasin to meet Parrot first". The Times of India. 27 August 1991. p. 20.
- ^ a b c d "Hendry survives scare and wins again". Snooker Scene. Birmingham: Everton's News Agency. October 1991. p. 23.
- ^ Turner, Chris. "Other Non-Ranking and Invition Events". cajt.pwp.blueyonder.co.uk. Chris Turner's Snooker Archive. Archived from the original on 16 February 2012. Retrieved 24 October 2012.