2019 OEC Taipei WTA Challenger – Doubles
| Doubles | |
|---|---|
| 2019 OEC Taipei WTA Challenger | |
| Champions |  Lee Ya-hsuan  Wu Fang-hsien | 
| Runners-up |  Dalila Jakupović  Danka Kovinić | 
| Score | 4–6, 6–4, [10–7] | 
Ankita Raina and Karman Thandi were the defending champions[1] but Thandi chose not to participate. Raina partnered alongside Bibiane Schoofs, but lost in the quarterfinals to Lee Ya-hsuan and Wu Fang-hsien.
Lee and Wu went on to win the title, defeating Dalila Jakupović and Danka Kovinić in the final, 4–6, 6–4, [10–7].
Seeds
.svg.png) Arina Rodionova / Arina Rodionova /.svg.png) Storm Sanders (semifinals) Storm Sanders (semifinals)
 Dalila Jakupović / Dalila Jakupović / Danka Kovinić (final) Danka Kovinić (final)
 Ankita Raina / Ankita Raina / Bibiane Schoofs (quarterfinals) Bibiane Schoofs (quarterfinals)
 Yana Sizikova / Yana Sizikova / Emily Webley-Smith (first round, retired) Emily Webley-Smith (first round, retired)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- ITF = ITF entry
- PR = Protected ranking
- SR = Special ranking
- SE = Special exempt
- JE = Junior exempt
- JR = Junior Accelerator Programme entrant
- CO = College Accelerator Programme entrant
- NG = Next Gen Accelerator Program entrant
- w/o = Walkover
- r = Retired
- d = Defaulted
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | .svg.png) Ar Rodionova .svg.png) S Sanders | 6 | 6 | ||||||||||||||||||||||||
|  E Chong  A Sutjiadi | 2 | 2 | 1 | .svg.png) Ar Rodionova .svg.png) S Sanders | 6 | 6 | |||||||||||||||||||||
|  N Dzalamidze  K Rakhimova | 6 | 6 |  N Dzalamidze  K Rakhimova | 3 | 3 | ||||||||||||||||||||||
|  C-w Hsu  Ya-hsi Lee | 4 | 3 | 1 | .svg.png) Ar Rodionova .svg.png) S Sanders | 3 | 4 | |||||||||||||||||||||
| 3 |  A Raina  B Schoofs | 6 | 77 |  Ya-hsu Lee  F-h Wu | 6 | 6 | |||||||||||||||||||||
| .svg.png) S Bandecchi  S-R Sekulic | 4 | 64 | 3 |  A Raina  B Schoofs | 6 | 3 | [9] | ||||||||||||||||||||
|  Ya-hsu Lee  F-h Wu | 6 | 6 |  Ya-hsu Lee  F-h Wu | 3 | 6 | [11] | |||||||||||||||||||||
| WC |  J Garland  Y-y Yang | 3 | 0 |  Ya-hsu Lee  F-h Wu | 4 | 6 | [10] | ||||||||||||||||||||
|  I Shinikova  P Thombare | 7 | 6 | 2 |  D Jakupović  D Kovinić | 6 | 4 | [7] | ||||||||||||||||||||
|  J Jebawy  A Riley | 5 | 3 |  I Shinikova  P Thombare | 3 | 4 | ||||||||||||||||||||||
|  I-h Cho  Y-t Cho | 6 | 3 |  I-h Cho  Y-t Cho | 6 | 6 | ||||||||||||||||||||||
| 4 |  Y Sizikova  E Webley-Smith | 1 | 0r |  I-h Cho  Y-t Cho | 4 | 4 | |||||||||||||||||||||
|  N Bains  A Hesse | 6 | 6 | 2 |  D Jakupović  D Kovinić | 6 | 6 | |||||||||||||||||||||
|  P-h Chen  Y-c Hsieh | 3 | 4 |  N Bains  A Hesse | 65 | 4 | ||||||||||||||||||||||
|  K Okamura  P Plipuech | 6 | 65 | [7] | 2 |  D Jakupović  D Kovinić | 77 | 6 | ||||||||||||||||||||
| 2 |  D Jakupović  D Kovinić | 2 | 77 | [10] | |||||||||||||||||||||||
References
- ^ "Ankita Raina-Karman Kaur Thandi pair wins WTA Taipei Open title". The Times of India. 18 November 2018.