2019 Thoreau Tennis Open – Doubles

Doubles
2019 Thoreau Tennis Open
Champions	Angela Kulikov Rianna Valdes
Runners-up	Elizabeth Halbauer Ingrid Neel
Score	7–6(7–3), 4–6, [17–15]

This was the first edition of the tournament.^[1]

Angela Kulikov and Rianna Valdes won the title, defeating Elizabeth Halbauer and Ingrid Neel in the final, 7–6^(7–3), 4–6, [17–15].^[2]

	First round							Quarterfinals							Semifinals							Final
	1	D Kovinić N Stojanović	6	6
		M Mateas P Udvardy	2	4				1	D Kovinić N Stojanović	3	3
		E Halbauer I Neel	6	6					E Halbauer I Neel	6	6
		K Fahey M Westby	1	4												E Halbauer I Neel	77	77
	4	O Govortsova V Savinykh	68	7	[10]										4	O Govortsova V Savinykh	63	64
		A Bondár P Ormaechea	710	5	[1]			4	O Govortsova V Savinykh	5	6	[10]
		Z Hives B Woolcock	6	2	[5]				S Marand C Whoriskey	7	4	[6]
		S Marand C Whoriskey	3	6	[10]																		E Halbauer I Neel	63	6	[15]
	WC	B Collens N Semenovski	2	1																		WC	A Kulikov R Valdes	77	4	[17]
		S Xu X You	6	6					S Xu X You	1	2
		M Bolkvadze E Gorgodze	77	5	[4]			3	P-h Chen Y-c Hsieh	6	6
	3	P-h Chen Y-c Hsieh	64	7	[10]										3	P-h Chen Y-c Hsieh	2	4
		S Chang A Mueller	3	2											WC	A Kulikov R Valdes	6	6
	WC	A Kulikov R Valdes	6	6				WC	A Kulikov R Valdes	7	4	[10]
	WC	E Campbell A Robins	2	0				2	B Schoofs Y Wickmayer	5	6	[7]
	2	B Schoofs Y Wickmayer	6	6

• Main Draw