Chorula
Chorula | |
|---|---|
Village | |
![]() Church | |
![]() Chorula | |
| Coordinates: 50°32′N 17°58′E / 50.533°N 17.967°E | |
| Country | |
| Voivodeship | Opole |
| County | Krapkowice |
| Gmina | Gogolin |
| Population | 640 |
| Website | http://www.chorula.pl/ |
Chorula [xɔˈrula] is a village in the administrative district of Gmina Gogolin, within Krapkowice County, Opole Voivodeship, in south-western Poland.[1] It lies approximately 7 km (4 mi) north-west of Gogolin, 8 km (5 mi) north of Krapkowice, and 15 km (9 mi) south of the regional capital Opole.
References
- ^ "Główny Urząd Statystyczny" [Central Statistical Office] (in Polish). To search: Select "Miejscowości (SIMC)" tab, select "fragment (min. 3 znaki)" (minimum 3 characters), enter town name in the field below, click "WYSZUKAJ" (Search).


