Seward Township, Kosciusko County, Indiana

Seward Township
Township
Coordinates: 41°06′29″N 85°56′46″W / 41.10806°N 85.94611°W / 41.10806; -85.94611
CountryUnited States
StateIndiana
CountyKosciusko
Government
 • TypeIndiana township
Area
 • Total
36.27 sq mi (93.9 km2)
 • Land34.98 sq mi (90.6 km2)
 • Water1.3 sq mi (3 km2)
Elevation
[1]
876 ft (267 m)
Population
 (2020)[2]
 • Total
2,280
 • Density73.4/sq mi (28.3/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code18-68796[3]
GNIS feature ID453840

Seward Township is one of seventeen townships in Kosciusko County, Indiana, United States. As of the 2020 census, its population was 2,280 (down from 2,567 at 2010[4]) and it contained 1,357 housing units.

Seward Township was organized in 1859.[5]

Geography

According to the 2010 census, the township has a total area of 36.27 square miles (93.9 km2), of which 34.98 square miles (90.6 km2) (or 96.44%) is land and 1.3 square miles (3.4 km2) (or 3.58%) is water.[4]

Cities and towns

References

  1. ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ^ "Census Bureau profile: Seward Township, Kosciusko County, Indiana". United States Census Bureau. May 2023. Retrieved April 2, 2024.
  3. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  4. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
  5. ^ Biographical and Historical Record of Kosciusko County, Indiana. Lewis Publishing Company. 1887. p. 728.


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