1890 Belgian general election|
|
|
|  
 | 
First party
 | 
Second party
 |  
|  
 | 
 
 | 
 
 |  
| Leader
 | 
Auguste Beernaert
 | 
 |  
| Party
 | 
Catholic
 | 
Liberal
 |  
| Leader's seat
 | 
Candidate for PM
 | 
 |  
| Seats before
 | 
98 seats
 | 
40 seats
 |  
| Seats won
 | 
29
 | 
40
 |  
| Seats after
 | 
94
 | 
44
 |  
| Seat change
 | 
  4
 | 
  4
 |  
| Popular vote
 | 
17,253
 | 
20,829
 |  
| Percentage
 | 
45.15%
 | 
54.51%
 |  
  | 
 
 | 
Partial general elections were held in Belgium on 10 June 1890.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 94 of the 138 seats.[2]
Under the alternating system, elections were held in only four out of the nine provinces: Hainaut, Limburg, Liège and East Flanders. Thus, only 69 seats out of the 138 were up for election. Additionally, a special election was held in Neufchâteau on 3 June 1890.[3]
Results
Chamber of Representatives
  | 
|---|
| Party | Votes | % | Seats | 
|---|
| Won | Total | +/– | 
|---|
 | Liberal Party | 20,829 | 54.51 | 40 | 44 | +4 | 
 | Catholic Party | 17,253 | 45.15 | 29 | 94 | –4 | 
 | Belgian Labour Party | 98 | 0.26 | 0 | 0 | New | 
 | Others | 30 | 0.08 | 0 | 0 | 0 | 
| Total | 38,210 | 100.00 | 69 | 138 | 0 | 
 | 
| Total votes | 38,210 | – |  | 
|---|
| Registered voters/turnout | 59,452 | 64.27 |  | 
|---|
| Source: Mackie & Rose,[4] Sternberger et al. | 
Constituencies
The distribution of seats among the electoral districts was as follows:[5]
References